5y^2+10=4y

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Solution for 5y^2+10=4y equation: 



5y^2+10=4y

We move all terms to the left:

5y^2+10-(4y)=0

a = 5; b = -4; c = +10;
Δ = b2-4ac
Δ = -42-4·5·10
Δ = -184
Delta is less than zero, so there is no solution for the equation

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